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Given that

The Scalar product

if two vectors are perpendicular; Q=90degrees

then CosQ=0;

from (1)

(a

a

is this a correct solution for the above Question?

please can someone give me an opinion!

__a__=(a_{1},a_{2},a_{3}) and__b__=(b_{1},b_{2},b_{3}) by applying the Pythagoras rule, Prove that a_{1}b1+a_{2}b_{2}+a_{3}b_{3}=0 if__a__and__b__perpendicularThe Scalar product

__a__.b = |__a__||__b__|CosQ -------------(1)if two vectors are perpendicular; Q=90degrees

then CosQ=0;

from (1)

__a__.__b__=0(a

_{1},a_{2},a_{3}).(b_{1},b_{2},b_{3})=0a

_{1}b_{1}+a_{2}b_{2}+a_{3}b_{3}=0is this a correct solution for the above Question?

please can someone give me an opinion!

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